For discuss class of X-4, X-5, X-6
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1. A magnified, inverted image is located a distance of 32.0 cm from a double convex lens with a focal length of 12.0 cm. Determine the object distance and tell whether the image is real or virtual.
2. A 2.8-cm diameter coin is placed a distance of 25.0 cm from a double concave lens that has a focal length of -12.0 cm. Determine the image distance and the diameter of the image.
74 komentar:
1. s’ =32 cm
f = 12 cm convex-convex (+)
s = ??
1/f= 1/s +1/s’
1/12= 1/s +1/32
1/s = 32/384 – 12/384
S = 19,2 cm
(real)
2. Diameter coin =2,8 cm
f= - 12 cm concave (-)
s= 25 cm
s’ =???
1/f= 1/s +1/s’
1/-12 = 1/25 +1/s’
1/s’= -25/ 300 – 12/300
1/s’ = -13 /300
= 8,1 cm (terbalik)
D=h
h’/h = s’/s
d=8,1 x 2,8 /25
=0,9
sarah (28) X6
1. Dik : s':32cm
f :12 cm
Double convex lens (f:(+))
Dit : s?
Jwb : 1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
96/5 = s
19,2 cm = s
(Real, inverted, enlarged)
2. Dik : f:-12cm
diameter:2,8 cm
s:25 cm
Double concave lens(f (-))
Dit : s' and diameter of image?
Jwb : 1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/-12 - 1/25 = 1/s'
-25/300 - 12/300 = 1/s'
-37/300 = 1/s'
300/-37 = s'
-8,1 = s'
Diameter = h (height), so
h'/h = |s'/s|
h'/2,8 = 8,1/25
h = 8,1 x 2,8
---------
25
22,68
= ----- = 0,9 cm
25
Yuniar Sinta Dewi (32) X-6
1). dik:
s': 32cm
f : 12cm (double konvex) f(+)
dit:
s : ....?
jawab :
1/f =1/s+1/s'
1/12=1/s+1/32
1/s =1/12-1/32
1/s =8/96-3/96
1/s =5/96
s =96/5
s = 19,2 cm
(real)
2). dik:
f= -12cm (double concave) f(-)
d= 2.8cm d=h
s= 25cm
dit:
s'=....?
diameter of images?
jawab:
1/f =1/s+1/s'
1/-12=1/25+1/s'
1/s' =- 1/12-1/25
1/s' =-25/300-12/300
1/s' =-37/300
s' = 300/37
s' = -8,1 cm
diameter of images?
h'/h =s'/s
h'/2,8=8,1/25
h' = 2,8 x 8,1 :25
h' = 0,9cm
Ayu Kurniasih (6) X-5
1. diket:s'=32 cm
f= 12 cm (double convex) (+)
dit:s...?
jwb:1/f=1/s+1/s'
1/12=1/s+1/32
1/s =8/96-3/96
1/s =5/96
s =96/5
s =19,2 cm (real)
2. Diket: diameter coinn = 2,8 cm
f = -12 cm concaf lens (-)
s = 25 cm
Dit: s' and diameter of the
image...?
jwb: 1/f =1/s+1/s'
1/-12=1/25+1/s'
1/s' =1/-12-1/25
1/s' =-25/300 - 12/300
1/s' = -37/300
s' =-300/37
s' =-8,1 cm
Diameter of the image:
h'/h = |s'/s|
h'/2,8= 8,1/25
h'.25 = 8,1 . 2,8
h' = 22,68 /25
h' = 0,9 cm
Rika anggoro venny x-6 (26)
1. Dik : S' = 32 cm
f = 12 cm
Dit : S dan Sifat ?
Jawab : 1/f = 1/s + 1/s'
1/12= 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
s = 19,2 cm
(Real,inverted,magnified).
2. Dik : d = 2,8 cm
s = 25 cm
f = - 12 cm
Dit : S' dan d' ?
Jawab : 1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/-12 - 1/25 = 1/s'
-25/300 - 12/300 = 1/s'
-37/300 = 1/s'
S' = - 8,11 cm
Diameters of image :
d'/d = s'/s
d'/2,8 = 8,11/25
d' = 8,11/25 x 2,8
d' = 0,91 cm
MAULA HAKIM (20) X-5
1)Uknown :S'=32 cm
f =12 cm
Question :S and Characteristic of lens????
Answer :1/f = 1/s + 1/s'
1/12= 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
s = 19,2 cm
(Real,inverted,magnified)
2)Uknown :d=2,8 cm
s=25 cm
f=-12 cm
Question :S' and d' ?
Answer :1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/-12 - 1/25 = 1/s'
-25/300 - 12/300 = 1/s'
-37/300 = 1/s'
S' = -8,108 cm
Diameters:d'/d = |-s'/s|
d'/2,8 = 8,11/25
d' = 8,11/25 x 2,8
d' = 0,908 cm
Senko Diarnise(25) class: X-4
Name : Harun Usman
Class : X - 6
Absent : 10
Physic Question :
1. Known : S' = 32 cm
f = 12 cm
Ask :
A. S
B. form of the image?
Answer:
1/f = 1/s + 1/s'
1/12= 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
s = 19,2 cm
Form Of Image :Real,inverted,magnified.
2. Known : d = 2,8 cm
s = 25 cm
f = - 12 cm
Ask :
A. S'
B. d'
Answer : 1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/-12 - 1/25 = 1/s'
-25/300 - 12/300 = 1/s'
-37/300 = 1/s'
S' = - 8,11 cm
image's diameter :
d'/d = s'/s
d'/2,8 = 8,11/25
d' = 8,11/25 x 2,8
d' = 0,91 cm
1. s': 32cm
f: 12 cm [Double-Convex (+)]
s: ?
Answer:
The formula is
1/f = 1/s + 1/s'
so,
1/12 = 1/s + 1/32
1/12 - 1/32 = 1/s
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19,2 cm
(Real, inverted, magnified)
2. Diameter coin :2,8 cm
f: - 12 cm concave (-)
s: 25 cm
s’: ?
Answer:
The formula is
1/f= 1/s +1/s’
so,
1/-12 = 1/25 +1/s’
1/s’= -25/ 300 – 12/300
1/s’ = -13 /300
s' = 8,1 cm (inverted)
Diameter of images:
d’/d = s’/s
2,8/d = 8,1/25
d = 2,8 x 8,1/25
=0,9 cm
Ilham Ramadhan (16) X-5
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 = s’
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
Khusna Mar’ati (17)
X-6
1. Known : s'= 32 cm
f = 12 cm -> double convex(+)
Question : s?
Answer : 1/f = 1/s + 1/s'
1/s = 1/f - 1/s'
= 1/12 - 1/32
= 8/96 - 3/96
= 5/96
s = 96/5 = 19,2 cm
Real, inverted, magnified
2. Known : d = 2,8 cm
s = 25 cm
f = -12 -> double concave(-)
Question : s'?
Answer : 1/f = 1/s + 1/s'
1/s' = 1/f - 1/s
= 1/-12 - 1/25
= 25/300 - (-12)/300
= 25/300 + 12/300
= 37/300
s' = 300/37 = 8,11 cm
d'/d = s'/s
d'/2 = 8,11/25
d' = 8,11/25 x 2,8
= 0,91 cm
Rabiana Nur Awalia
X-5 (26)
Number 1.
Known:
F= 12cm (Double Convex +)
S'= 32
Question: S
Answer:
1/f=1/s+1/s'
1/12 = 1/s+1/32
1/s= 1/12 - 1/32
1/s = 8/96 -3/96
1/s = 5/96
s= 96/5
s= 19,2cm (Real , Inverted , Magnified)
Number 2:
Known:
f= 12cm (Double Concave -)
s= 25cm
h= 2,8cm
Question:
s' and h'
Answer:
1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/s' = 1/25 + 1/12
1/s' = 12/300 + 25/300
1/s' = 37/300
s'= 300/37 = 8,1cm
h'/h = s'/s
h'/2,8=8,1/2,5
h' = 8,1x2,8/25
=0,91
BY: SULTHAN NABIL (x-5)
(031)
1. know: s'= 32,0 cm
f = 12,0 cm
ask: s...?
answer: 1/f= 1/s+ 1/s'
1/12=1/s+1/32
1/s= 1/12-1/32
=16/192-6/192
= 10/192
s= 19,2 cm (real)
2. know: d= 2,8 cm
s=25,0 cm
f= -12,0 cm (concave)
ask: s'....?
D...?
answer: 1/f= 1/s'+1/s
1/-12=1/s'+1/25
-1/12-1/25=1/s'
-25/300-12/300=1/s'
-37/300=1/s'
-8,11=s'
D=H
M= s'/s
M= 8,11/25
M= 0,3244
M=h'/h=
0,3244= h'/2.8
h'= 0,3244 X 2,8
h'= 0,91 cm
Dzihni Nur Shabrina (05) X-6
1. Uknonw: s'=32 cm
f=12 cm ,double convex(+)
Questions:s:....?
characteristic of lens:..?
Answer:
1/f =1/s + 1/s'
1/12=1/s + 1/32
1/s =1/12 - 1/32
1/s =8/96 - 3/96
1/s =5/96
s = 19,2 cm
Characteristic of lens: Real,inverted,magnified
2.Uknonw : diameter coin's = 2,8 cm
s = 25 cm
f = -12cm ,
concave lens (-)
Questions:s'=....?
h'=....?
(diameter images coin's)
Answer:
1/f = 1/s + 1/s'
1/-12= 1/25 + 1/s'
1/s' =1/-12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s'=300/-37
s'=-8,1 cm
Diameter coin's = h , So
h'/h = s'/s
h'/2,8 cm = -8,1 cm / 25 cm
h' = 2,8 cm x -8,1 / 25
h' = -0,9 cm
Inggid Putri N Saiya
17 / X-5
1. known:
S' = 32 cm
f = 12 cm Double convex lens (+)
Ask : S dan Sifat ?
Answer : 1/f = 1/s + 1/s'
1/12= 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
s = 19,2 cm
(Real,inverted,magnified).
2. Known :
d = 2,8 cm
s = 25 cm
f = - 12 cm
Ask : S' dan d' ?
Answer : 1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/-12 - 1/25 = 1/s'
-25/300 - 12/300 = 1/s'
-37/300 = 1/s'
S' = - 8,1 cm
Diameters of image :
d'/d = s'/s
d'/2,8 = 8,11/25
d' = 8,11/25 x 2,8
d' = 0,91 cm
mukholifahtin ajijah
X-5 / 24
1. s'=32 cm
f =12 cm
1/s=1/f-1/s'
1/s=1/12-1/32
1/s=8/96-3/96
1/s=5/96
s=96/5=19,2 cm
so the image is real
2. s=25 cm
f=-12cm
d=2.8cm
h=d=2,8cm
1/s'=1/f-1/s
1/s'=1/-12 - 1/25
1/s'=-25/300 - 12/300
1/s'=-37/300
s'=-300/37
s'=-8,1 cm
|d'/d| = s'/s
d'/2,8=8,1/25
d'=2,8x8,1/25=0,9
Daniel X-5 7
1.Known:
s' = 32 cm
f = 12 cm
convex (+)
s? real or virtual?
1/f = 1/s + 1/s'
1/s + 1/s' = 1/f
1/s = 1/f - 1/s'
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19,2 cm
(real)
2.Known:
d = 2,8 cm
d = h
s = 25 cm
f = 12
concave (-)
s'? h'?
1/f = 1/s + 1/s'
1/s + 1/s' = 1/f
1/s' = 1/f - 1/s
1/s' = 1/-12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = 300/-37
s' = -8,1 cm
h'/h = |s'/s|
h' = s'/s*h
h' = 8,1/25*2,8
h' = 0,9 cm
Seavhira Dianmurdedi X5
1. Dik: s'=32cm
f=12 cm two convex (f=+)
Dit: s?
1/f=1/s+1/s'
1/s=1/f-1/s'
1/s=1/12-1/32
1/s=32/384-12/384
s=19.2 cm (real,inverted, enlarge)
2.Dik: D=2,8 cm
f=-12 cm two concave (f=-)
s=25 cm
Dit: s' and diameter of image?
1/f=1/s+1/s'
1/s'=1/f-1/s
1/s'=1/-12-1/25
1/s'=-25/300-12/300
s'=8,1 cm
diameter of image=height
h'/h=-s'/s
h'/2,8=8,1/25
h'=2,8x8,1/25
h'=0,9 cm
Lutfia Zahra X-6(18)
1. Dik : s': 32 cm
f : 12 cm (+) because
it's a convex lens
Dit : s and shadow properties?
Jawab :*)1/f = 1/s + 1/s'
1/12= 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
s = 19,2 cm
*)Shadow Properties:
Real,inverted,magnified
2. Dik : d = 2,8 cm
s = 25 cm
f = - 12 cm (because
it's a concav lens)
Dit : s' and d' ?
Jawab :*)1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/-12 - 1/25 = 1/s'
-25/300 - 12/300 = 1/s'
-37/300 = 1/s'
s' = - 8,108 cm
*)d'/d = s'/s
d'/2,8 = 8,11/25
d' = 8,11/25 x 2,8
d' = 0,908 cm
Name : Panji Arie Prabowo (025)
Class : X5
1. Dik : s':32cm
f :12 cm Double convex lens (f=+)
Dit : s?
Jwb : 1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
1/s = 5/96
96/5 = s
s = 19,2 cm
(real, inverted, magnified)
2. Dik : f=-12cm concave (-)
diameter:2,8 cm
s:25 cm
Dit : s' and diameter of image?
Jwb : 1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/s' = 1/-12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = 300/-37
s' = -8,1
Diameter = h
h'/h = |s'/s|
h'/2,8 = 8,1/25
h = 8,1 x 2,8/25
= 0,9 cm
HANYFA AYU DININGRUM (9)
X-6
1. - known : s' = 32cm
f = 12cm
- ask : s...?
form of object/
_ answer
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19.2cm
(real)
2. -known : d = 2.8cm
s = 25cm
f = -12cm
-ask : s'...?
d'/h'...?
-answer
1/f = 1/s + 1/s'
-1/12 = 1/25 + 1/s'
1/s' = -1/12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = -300/37
s' = -8.1
d=h
h'/h = s'/s
h'/2.8 = 8.1/25
h' = 8.1x2.8/25
h' = 0.9cm
fauzan abdillah (07) X6
1. diketahui : s' = 32.0 cm
f = 12.0 cm (+)
ditanya : s..?
jawab :
1/f = 1/s + 1/s'
1/s = 1/f - 1/s'
1/s = 1/12 cm - 1/32 cm
1/s = (8/96 - 3/96) cm
1/s = 5/96 cm
s = 96/5 cm = 19.2 cm -> real
2. diketahui :
diameter koin = 2.8 cm
f = (-12)cm (-)
s = 25 cm
ditanya : s'...??
jawab :
1/f= 1/s +1/s’
1/-12 = 1/25 +1/s’
1/s’= -25/ 300 – 12/300
1/s’ = -13 /300
s' = 8,1 cm -> inverted
diameter :
d’/d = s’/s
2,8/d = 8,1/25
d = 2,8 x 8,1/25
=0,9 cm
Anita BellaDina(03) X-5
1.dik.s'= 32 cm
f = 12 cm (convex) f(+)
dit.s ?
1/f =1/s+1/s'
1/12=1/s+1/32
1/s =1/12-1/32
1/s =8/96-3/96
1/s =5/96
s =96/5
s = 19,2 cm
(real)
2.dik.d = 2,8 cm
s = 25 cm
f = - 12 cm (concave) f(-)
Dit.S' dan diameter of image ?
1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/-12 - 1/25 = 1/s'
-25/300 - 12/300 = 1/s'
-37/300 = 1/s'
S' = -8,11 cm
diameter image
d'/d = s'/s
d'/2,8 = 8,11/25
d' = 8,11/25 x 2,8
d' = 0,91 cm
Muhamad Hariz Ananto (23)
x-5
1. Unknown :
s= 32cm
f= 12cm (convex)(+)
Asked :
s= ???????????
Answer :
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19,2cm (Real,Inverted,Enlarged)
-----------------------------------
2. Unknown :
Diameter = 2,8cm
f = -12cm (concave) (-)
s = 25cm
Asked :
s' = ?????
d = ?????
Answer :
1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/s' = -1/12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = -300/37
s' = -8,1cm
------------------------
d = h'/h = s'/s
d = h'/2,8 = 8,1/25
h'= 2,8 x 8,1 / 25
h'= 0,9
Senoaji Dwi Hastomo (30) X-5
1. double convex lens, it means the focus (+).
s' = 32 cm
f = 12 cm
s = ?
answer: 1/f = 1/f + 1/s'
1/12= 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
s = 96/5 = 19.2 cm
So the object distance is 19.2 cm and the image is real.
2. Double concave lens, it means the focus is (-)
d = 2.8 cm *d = h
s = 25.0 cm
f = -12.0 cm
s' = ?
Answer : 1/f = 1/s + 1/s'
-1/12 = 1/25 + 1/s'
1/s' = -1/12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = -300/37 = -8.1 cm
so the image distance is -8.1 cm
to find the diameter of the image
h'/h = s'/s
h'/2.8 = 8.1/25
25h' = 8.1*2.8
25h' = 22.68
h' = 0.9 cm
so diameter of the image is 0.9 cm
Tias Agustiningrum (30)
x-6
1. s': 32cm
f: 12 cm {Double-Convex (+)}
s: ?
Answer:
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/12 - 1/32 = 1/s
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19,2 cm
(Real)
2. Diameter coin :2,8 cm
f: - 12 cm {concave (-)}
s: 25 cm
s’: ?
Answer:
1/f= 1/s +1/s’
1/-12 = 1/25 +1/s’
1/s’= -25/ 300 – 12/300
1/s’ = -13 /300
s' = -8,1 cm
Diameter of images:
d’/d = s’/s
d’/2,8 = 8,1/25
d’= 2,8 x 8,1/25
=0,9 cm
Kyendi Suramana P (X-5/19)
1.
Known :
Double convex lens is positive lens (+)
The characteristic image magnified and inverted
s’ = 32 cm
f = 12 cm
Asked :
s = …. ?
Solution :
1/f = 1/s+ 1/s'
1/12 = 1/s + 1/32
-1/s = 1/32 - 1/12
-1/s = 12/384 - 32/384
-1/s =(-20)/384
-s/1 = - 384/20
- s = - 19.2
s = 19.2
The image real because s’ = positive, and the image formed behind the lens
The form characteristic image = real, inverted, magnified
2.
Known :
double concave lens is negative lens (-)
Diameter coin = 2.8 cm
s = 25 cm
f = - 12 cm
Asked :
a. s’ = … ?
b. diameter image = … ?
Solution :
a.
1/f = 1/s+ 1/s^'
-1/12= 1/25+ 1/s'
-1/s' = 1/25 + 1/12
-1/s' = 12/300+25/300
-1/s' = 37/300
-s'/1 = 300/37
- s'= 8.1
s'= -8.1
b.
Diameter image = h’
Diameter object = h
h'/h = |s'|/|s|
h'/2.8 =|8.1|/|25|
h'= (8.1 x 2.8)/25
h'= 0.9 cm
The form characteristic of images : virtual, upright, minimize
HILMAN NUR FAIZI / X-6 . 11
1. s'=32 cm
f=12 cm (double convex (+))
s ?
=> s = (s'.f) : (s'-f)
s = (32.12) : (32-12)
s = (384) : (20)
s = 19,2 cm (inverted,real, enlarged)
2. D = 2,8 cm
f= -12 cm (double concave (-))
s= 25 cm
s' ?
=> s' = (s.f) :(s-f)
s' = (25.-12) : (25+12)
s' = 300 : 37
s' = 8,1 cm
h'/h = |s'/s|
h'/2,8= 8,1/25
h' = 8,1 . 2,8 : 25
h' = 0,9 cm
Mega Puspita (21) X5
1.
known :
s’ = 32 cm
f = 12 cm
double convex lens f(+)
ask :
s ?
real or virtual ?
answer :
s ?
1/s = 1/f - 1/s'
1/s = 1/12 - 1/32
1/s = 32/384 - 12/384
1/s = 20/384
384 = 20s
s = 19,2 cm
the image is (real, inverted, magnified)
2.
known :
diameter coin = 2,8 cm
s = 25 cm
double concave lens f(-)
f = -12
ask :
s' ?
d' ?
answer :
s' ?
1/s' = 1/f - 1/s
1/s' = -1/12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = -300/37
s' = -8,1 cm
d' ?
d' = h'
|h'/h| = |s'/s|
|h'/2,8| = |-8,1/25|
25h' = 22,68
h' = 22,68/25
h' = 0,91 cm
d' = 0,91 cm
Khairunnisa Solihah (18) X-5
1.
dik :
f : 12 double convex (+)
s' : 32
dit :
a. S ?
b. real or virtual ?
jwb :
a. 1/f= 1/s + 1/s'
1/s= 1/12 - 1/32
1/s= 8/96 - 3/96 = 5/96
S= 96/5 = 1,92
B. the picture is REAL
2.dik : d = 2,8
S = 2,5
F = - 12 concave (-)
dit :
a. s'
b. d'
jwb
a. 1/f = 1/s + 1/s'
1/s' = 1/-12 - 1/25
1/s' = - 25/300 - 12/300
1/si = -300/37 = - 8,1
b.d'/d = s'/s
d'/2,8 = -8,1/25
d' = -8,1 * 2,8 / 25
d' = 22,68 or 23
MICHELLE GLORIA MOHEDE
10.5 / 22
1. Known :
s' = 32,0 cm
f = 12, 0 cm
Questions :
s = ... ?
The image real/virtual ?
Answer :
1/s = 1/f-1/s'
1/s = 1/12-1/32
1/s = 8/96-3/96
1/s = 5/96
s = 96/5 = 19,2 cm
The image is real.
2. Known :
d = 2,8 cm
s = 25,0 cm
f = -12,0 cm
Questions :
s' = ... ?
d' = ... ?
Answer :
1/s' = -1/f-1/s
1/s' = -1/12-1/25
1/s' = -25/300-12/300
1/s' = -37/300
s' = -300/37 = -8,1 cm
d' = h'
then,
h'/h = s'/s
h'/2,8 = 8,1/25
25 h' = 22,68
h' = 22,68/25 = 0,9072 = 0,91 cm
so, d' = 0,91 cm
Name : Sarah Lorenza Caverina Purba
No. Absent : 27
Class : X-5
1. Known :
s'= 32cm
f = 12cm double convex lens(+)
Question : s ?
Answer :
a )1/f=1/s + 1/s'
1/12=1/s+1/32
1/s=1/12-1/32
1/s=8/96-3/96
1/s=5/96
s = 96/5 = 19,2 cm
b) (Real)
2.Known :
diameter coin/h : 2,8 cm
s = 25 cm
f = 12 cm concave(-)
Questions : s' ? and h' ?
a)1/f=1/s+1/s'
1/-12=1/25+1/s'
1/s'=1/-12 - 1/25
1/s'=-12/300 - 25/300
1/s'=-37/300
s' = -300/37 = -8,1 cm
b)h'/h=|s'/s|
h'/2,8=|-8,1/25|
h'=8,1*2,8 / 25
h'=0,9 cm
Friska Matdalena (14)
x-5
1. f= 12cm (double convex)(+)
s'= 32cm
S=.....??
answere:
*1/f=1/s +1/s'.
1/s= 1/12-1/32
1/s= 8/96-3/96
S= 96/5
S= 19,2cm (REAL).
2.f=-12cm(concave)(-) s=25cm
d=2,8cm (d=h)
S'=....?
Diameter of image...?
Answere:
* 1/f= 1/s+1/s'
1/s'=-1/12 - 1/25
1/s'= -25/300 - 12/300
1/s'= -37/300
s' = 300/37
s'= -8,1 cm..
*Diameter of images.
d=h
h'/h=s'/s
h'/2,8 = 8,1/25
h'= 2,8 x 8,1 : 25
h'= 0,91cm..
M.Aditya Rahman.G (21)
X-6
1.
dik :
f : 12 double convex (+)
s' : 32
dit :
a. S ?
b. real or virtual ?
jwb :
a. 1/f= 1/s + 1/s'
1/s= 1/12 - 1/32
1/s= 8/96 - 3/96 = 5/96
S= 96/5 = 1,92
B. the picture is REAL
2.dik : d = 2,8
S = 2,5
F = - 12 concave (-)
dit :
a. s'
b. d'
jwb
a. 1/f = 1/s + 1/s'
1/s' = 1/-12 - 1/25
1/s' = - 25/300 - 12/300
1/si = -300/37 = - 8,1
b.d'/d = s'/s
d'/2,8 = -8,1/25
d' = -8,1 * 2,8 / 25
d' = 22,68 / 25
d' = 0,9
MICHELLE GLORIA MOHEDE
10.5 / 22
1. dik :
s' = 32cm
f = 12 cm (+)
dit :
s ?
jawab :
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 32/384 - 12/384
1/s = 20/384
s = 384/20
s = 19,2
images is real because the object distance and the images distance is positive
2. dik :
diameter coin = 2,8 cm
f = -12 (concave)
s = 25 cm
dit :
s' ?
diameter images ?
jawab :
1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/s' = 1/-12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = 300/-37
s' = -8,1 (virtual)
diameter = h
h = 2,8 cm
s = 25 cm
s' =-8,1 cm
so,
h'/h = |s'/s|
h' = h x s'/s
h' = (2,8 . 8,1)/ 25
h' = 22,68 / 25
h' = 0,9 cm
diameter images is 0,9
Sayekti yuliyanti (28)
X-5
1. dik :
s' = 32cm
f = 12 cm (+)
dit :
s ?
jawab :
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 32/384 - 12/384
1/s = 20/384
s = 384/20
s = 19,2
images is real because the object distance and the images distance is positive
2. dik :
diameter coin = 2,8 cm
f = -12 (concave)
s = 25 cm
dit :
s' ?
diameter images ?
jawab :
1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/s' = 1/-12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = 300/-37
s' = -8,1 (virtual)
diameter = h
h = 2,8 cm
s = 25 cm
s' =-8,1 cm
so,
h'/h = |s'/s|
h' = h x s'/s
h' = (2,8 . 8,1)/ 25
h' = 22,68 / 25
h' = 0,9 cm
diameter images is 0,9
andina azka (x-5)
1.
Diketahui :
s` = 32 cm
f = +12 cm (karena lensa cembung, jadi positif)
Ditanya :
s = ...
Jawab =
1/f = 1/s + 1/s`
1/s = 1/f - 1/s`
1/s = 1/12 - 1/32
1/s = 32/384 - 12/384
1/s = 20/384
s = 384/20
s = 19.2 cm
Real (karena di belakang lensa)
Karakter : nyata, terbalik, diperbesar
2.
Diketahui :
s = 25 cm
f = -12 cm
d (diameter benda/koin) = 2.8 cm
Ditanya :
s` = ...
d` (diameter bayangan) = ...
Jawab :
1/f = 1/s + 1/s`
1/s` = 1/f - 1/s
1/s` = 1/-12 - 1/25
1/s` = -25/300 - 12/300
1/s` = -37/300
s` = 300/-37
s` = -8.1 cm
d = h
h`/h = |s`/s|
h` = |s`/s| x h
h` = |8.1/25| x 2.8
h` = 0.9 cm
Karakter : maya, tegak, diperkecil
Umi Latifah
X-5
32
on1. Known :
s' = 32,0 cm
f = 12,0 cm
Lens Is Double Convex (+)
Question :
s = ???? cm
Answer :
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
-1/s = 1/32 - 1/12
-1/s = 3/96 - 8/96
-1/s = -5/96
s = 19,2 cm
(Real,Magnified,Inverted)
2. Known :
h = 2,8 cm
s = 25,0 cm
f = - 12,0 cm
Lens Is Double Concave (-)
Question :
s' = ???? cm
h' = ???? cm
Answer :
1/f = 1/s + 1/s'
-1/12 = 1/25 + 1/s'
-1/s' = 1/12 + 1/25
-1/s' = 25/300 + 12/300
-1/s' = 37/300
s' = 8,1 cm
so...
h'/h = s'/s
h'/2,8 = 8,1/25
h' = 8,1 x 2,8 / 25
h' = 0,9072
h' = 0,91 cm
By : Achmad Ryan Iradat (01) X - 5
1. know:
s': 32cm
f : 12cm (double konvex)
question:
s : ????
answer:
1/f =1/s+1/s'
1/12=1/s+1/32
1/s =1/12-1/32
1/s =8/96-3/96
1/s =5/96
s =96/5
s = 19,2 cm (real,inverted,magnified)
2. know:
f= -12cm (double concave)
d= 2.8cm d=h
s= 25cm
question:
a. s'=????
b. diameter of images?
jawab:
a. 1/f =1/s+1/s'
1/-12=1/25+1/s'
1/s' =- 1/12-1/25
1/s' =-25/300-12/300
1/s' =-37/300
s' = 300/37
s' = -8,1 cm
b. diameter of images?
h'/h =s'/s
h'/2,8=8,1/25
h' = 2,8 x 8,1 :25
h' = 0,9cm
Name: Virdhi Dwi A.
No. Absent: 33
Class: X-5
Diket :
s' = 32cm
f = 12cm
Dit : s...?
Jawab :
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19.2cm
(real)
2. Diket :
d = 2.8cm
f = -12cm
s = 25cm
Dit : s'...?
d'/h'...?
Jawab :
1/f = 1/s + 1/s'
-1/12 = 1/25 + 1/s'
1/s' = -1/12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = -300/37
s' = -8.1
d=h
h'/h = s'/s
h'/2.8 = 8.1/25
h' = 8.1x2.8/25
h' = 0.9cm
Fadhliyah Tania (06) X-6
1. f = 12 cm ( double convex )
si = 32 cm
so = ???
1/f=1/si+1/so
1/12=1/so+1/32
1/so=1/12-1/32
=8/96-3/96
=5/96
so=96/5=19,2 cm ( real )
2. do = 2,8 cm
f = -12 cm ( double concave )
so = 25 cm
si = ??
di = ??
1/f=1/si+1/so
1/si=-1/12-1/25
=-25/300-12/300
=-37/300
si=-300/37=-8,11
di/do=|si/so|
di=2,8X8,1/25
=0.91 cm
gerald deo c tumbol
x5/15
1)
Dik : s' = 32 cm
f = 12 cm
Dit : a. s...?
b. real / virtual...?
jwb :
a. 1/s = 1/f - 1/s'
= 1/12 - 1/32
= (8 - 3) : 96
1/s = 5 / 96
s = 96/5
s = 19,2 cm
b. real , because image and objeck are positive
2)
Dik : d = 2,8 cm
s = 25 cm
f = -12 cm
Dit : a. s'...?
b. d'...?
jwb :
a. 1/s' = 1/f - 1/s
= -1/12 - 1/25
= (-25 - 12) : 300
1/s' = -37/300
s' = -300/37
s' = -8,11 cm
b. |s'/s| = |d'/d|
8,1/25 = d'/2,8
d = (2,8 x 8,1):25
d =0,911 cm
Nama : EDWARD JONATHAN
Kelas: X-5
No : 10
meinita dian pratiwi
x4 (11)
1. known :
~ s’=32 cm
~ f = 12 cm (double convex (=))
ask : s?
answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
19,2 = s
so, s = 19,2 (Real, inverted, enlarged)
2. known :
~ d = 2,8 cm
~ s’ = 25 cm
~ f = -12 (double concave lens (-))
ask : s’???? and diameter of images ??
answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12 - 1/25 = 1/s’
-25/300 - 12/300 = 1/s’
-37/300 = 1/s’
-8,10 = s’
Diameters of image:
d'/d = s'/s
d'/2,8 = [-8,11/25]
d'/2,8 = 0,324
d' = 0,324 x 2,8
d' = 0,9
A) SI =32CM, F= 12CM, S=?
1/S +1/SI = 1/F
1/S = 1/F-1/ SI = 1/12 – 1/32
=20/32.12= 5/96
S= 96/5 = 19,2
DIPERBESAR
TERBALIK = NYATA
B) D=2,8; s=25; f=-12
B.1) SI = sxf/s-f
= 25x(-12)/25-(-12)
= 300/-37 = 8,1 MAYA, TEGAK
B.2) dl /d = SI /S
dl = lSI /Sl . d
= l300/37x25l x 2,8
= 0,32 x 2,8 =0,9 DIPERKECIL
1.Known:
s' = 32 cm
f = 12 cm
The lens : doule convex
Find out :
a) s
b) real or virtual
1/f = 1/s + 1/s'
1/s + 1/s' = 1/f
1/s = 1/f - 1/s'
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19,2 cm
b) REAL
2. Known:
The lens : double concave
d = 2,8 cm
d = h
s = 25 cm
f = 12
find out : the s' and d'
1)looking for s' :
1/f = 1/s + 1/s'
1/s + 1/s' = 1/f
1/s' = 1/f - 1/s
1/s' = 1/-12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = 300/-37
s' = -8,1 cm
2) looking for h' :
because d' = h' so..
h'/h = |s'/s|
h' = s'/s.h
h' = 8,1/25.2,8
h' = 0,9 cm
Fadilah Amalia Husna
X-5
12
1. known :
~ s’= 32 cm
~ f = 12 cm Convex-Convex (+)
~ s = ?
answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12 - 1/32 = 1/s
8/96 - 3/96 = 1/s
5/96 = 1/s
19,2 = s
so, s = 19,2 (Real, inverted, enlarged)
2. known :
~ d = 2,8 cm
~ s’= 25 cm
~ f = -12 cm concave-concave (-)
~ s’= ?
~ diameter of images = ?
answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12 - 1/25 = 1/s’
-25/300 - 12/300 = 1/s’
-37/300 = 1/s’
-8,10 = s’
Diameters of image:
d'/d = s'/s
d'/2,8 = [-8,11/25]
d'/2,8 = 0,324
d' = 0,324 x 2,8
d' = 0,9
Muhammad Fathur Rahman (19) X-6
1). dik:
s': 32cm
f : 12cm (double konvex) f(+)
dit:
s : ....?
jawab :
1/f =1/s+1/s'
1/12=1/s+1/32
1/s =1/12-1/32
1/s =8/96-3/96
1/s =5/96
s =96/5
s = 19,2 cm
(real,inverted,magnified).
2. Dik : f:-12cm
diameter:2,8 cm
s:25 cm
Double concave lens f (-)
Dit : s' and diameter of image?
Jawab
1/f= 1/s +1/s’
1/-12 = 1/25 +1/s’
1/s’= -25/ 300 – 12/300
1/s’ = -13 /300
= -8,1 cm (inverted)
diameter of images?
h'/h =s'/s
h'/2,8=8,1/25
h' = 2,8 x 8,1 :25
h' = 0,9cm
Junifar Ridwan Pratama (16)
Kelas X-6
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens is positive (+)
The characteristic image magnified and inverted
Ask :
s =…??
Form of image = ….?
Solution :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12 - 1/32 = 1/s
32/384 - 12/384 = 1/s
20/384 = 1/s
s = 384/20 = 19,2 cm
The form of image = real, inverted, magnified
2. Known :
Dimater coin = h = 2,8 cm
s = 25 cm
f = -12 cm. double concave lens is negative (-)
Ask :
a. s’ =….?
b. Diameter image = h’ =…?
Solution :
a. 1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
s’ = 8,1 cm
b. h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = (8,1 x 2,8)/25
h’ = 0,9 cm
The form characteristic of images : virtual, upright, minimize
Irna Lita (14)
X-6
1.
Diketahui :
s'=32
f=12
Ditanya : s= ?
Jawab :
1/s + 1/s' =1/f
1/s = 1/f - 1/s'
= 1/12 - 1/32
= 32/32 - 12/12
= 20/32.12
1/s = 5/96
s = 96/5
= 19,2 cm
diperbesar,terbalik , nyata.
2.
Diketahui :
d = 38
s = 25
f = -12
Ditanya : a) s'
b) d'
Jawab :
a) s' = s x f / s - f
s' = 25 x (-12) / 25(-12)
s' =300 / -37
= -300/37
= -8,1 (maya , tegak)
b) d'/d = s'/s
d' = s'/s x d
= 300/37 x 25 | x 2.8
= 300/ 925 x 2,8
= 0,32 x 2,8
= o,89
(diperkecil)
Probo Sutejo Muta'alimin (17)
X4
1. s' = 32 cm
f = 12 cm
convex-convex (+)
Dit :
s = ???
Answer :
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 32/384 - 12/384
1/s = 20/384
s = 19,2 cm (real, inverted, magnified)
2. D = 2,8 cm d = h
s = 25 cm
f = -12 cm
concave (-)
Dit :
s' = ???
Answer :
1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/s' = 1/-12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -13/300
s' = -8,1 cm
d = h
h'/h = s'/s
h'/2,8 = 8,1/25
h = 2,8 x 8,1/ 25
h = 0,9 cm
d = h = 0,9 cm
Desyita Safira (03)
10-6
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 = s’
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
annisa dela yuliani X6 01
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 = s’
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
annisa dela yuliani
X6 (01)
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 = s’
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
annisa dela yuliani x6 01
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 = s’
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
annisa dela yuliani x6 01
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 = s’
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
annisa dela yuliani X6 01
1. Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 = s’
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
annisa dela yuliani X6 01
dian fitriani X-4/03
Known :
s’ = 32 cm
f =12 cm. Double convex lens (+)
Ask :
s =...?
Form of image =...?
Answer :
1/f = 1/s + 1/s’
1/12 = 1/s + 1/32
1/12-1/32 = 1/s
8/96-3/96 = 1/s
5/96 = 1/s
1/19,2 = 1/s
19,2 = s
Form of image = real
2. Known :
d = h = 2,8 cm
s = 25 cm
f = -12 cm. Double concave (-)
Ask :
s’ =...?
d’ = h =...?
Answer :
1/f = 1/s + 1/s’
1/-12 = 1/25 + 1/s’
1/-12-1/25 = 1/s’
-25/300-12/300 = 1/s’
-37/300 = 1/s’
300/-37 = s’
-8,1 cm = s’ (terbalik)
D=h
h’/h = [s’/s]
h’/2,8 = [8,1/25]
h’ = 8,1 x 2,8 :25
h’ = 0,9 cm
The form characteristic of images : virtual, upright, minimize
1. Known :
F= 12cm (Double Convex +)
S'= 32
Question: S
Answer:
1/f=1/s+1/s'
1/12 = 1/s+1/32
1/s= 1/12 - 1/32
1/s = 8/96 -3/96
1/s = 5/96
s= 96/5
s= 19,2cm (Real , Inverted , Magnified)
Number 2:
Known:
f= 12cm (Double Concave -)
s= 25cm
h= 2,8cm
Question:
s' and h'
Answer:
1/f = 1/s + 1/s'
1/-12 = 1/25 + 1/s'
1/s' = 1/25 + 1/12
1/s' = 12/300 + 25/300
1/s' = 37/300
s'= 300/37 = 8,1cm
h'/h = s'/s
h'/2,8=8,1/2,5
h' = 8,1x2,8/25
=0,91
DESY ALDEWISTA X5
1.Dik : Si = 32 cm
f = 12 cm (Double Convex Lens (+))
Dit : a. So ?
b. Real or Virtual ?
Jawab:
a. 1/f = 1/Si + 1/So
1/f - 1/Si = 1/So
1/12 - 1/32 = 1/So
8/96 - 3/96 = 1/So
5/96 = 1/So
1/So = 5/96
So = 96/5
So = 19,2 cm.
b. (Real,Inverted, and Magnified).
2)
Dik : Do = 2,8 cm
So = 25 cm
f = -12 cm (Double Concave Lens (-))
Dit : a. Si ?
b. Di = Hi ?
jwb :
a. 1/f = 1/Si + 1/So
1/f - 1/So = 1/Si
1/-12 - 1/25 = 1/Si
-25/300 - 12/300 = 1/Si
-37/300 = 1/Si
Si = -300/37
Si = - 8,108 = - 8,1 cm.
b. Do = Ho
Hi/Ho = Si/So
Hi/2,8 = 8,1/25
Hi = (8,1 x 2,8) : 25
Hi = 0,9072 = 0,91
Hi = Di = 0.91 cm.
Nama : Everton M. Sumampouw
Kelas: X-5 ( Lima )
No. : 11 ( Sebelas ).
1. dik :s'= 32 cm
f = 12 cm(double convex)(+)
dit : s...?
jwb : 1/f=1/s+1/s'
1/12=1/s+1/32
1/s =8/96-3/96
1/s =5/96
s =96/5
s =19,2 cm (real)
2. Dik : diameter coinn = 2,8 cm
f = -12 cm concaf lens (-)
s = 25 cm
Dit: s' and diameter of the
image...?
jwb: 1/f =1/s+1/s'
1/-12=1/25+1/s'
1/s' = 1/-12-1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = -300/37
s' = -8,1 cm
Diameter of the image:
h'/h = |s'/s|
h'/2,8 = 8,1/25
h'.25 = 8,1 . 2,8
h' = 22,68 /25
h' = 0,9 cm
Gladys Kusuma Wardani X-6 (08)
1.)Dik :S’ = 32 cm
f = 12 cm double convex {f (+)}
Dit : S = ? and Sifat Bayangan?
Answer : 1/f = 1/s + 1/s’
1/s = 1/f – 1/s’
1/s = 1/12 - 1/32
1/s = 8/96 – 3/96
1/s = 5/96
s = 96/5
s = 19,2 cm
{ Real, inverted, magnified }
2.)Dik : S = 25 cm
F = -12 cm concave lens(-)
Diameter = 2,8 cm
Dit : a.) S’ = ?
b.) Diameter bayangan?
Answer :a.)1/f = 1/s + 1/s’
1/s’ = 1/f – 1/s
1/s’ = 1/-12 – 1/25
1/s’ = -25/300 – 12/300
1/s’ = -37/300
S’ = 300/-37
S’ = -8,1 cm
b.) Diameter = tinggi benda (h)
h’/h = s’/s
h’ = h x s’/s
h’ = 2,8 x 8,1/25
h’ = 22,68/25
h’ = 0,9 cm
Dina Purwati (04) X6.
1.
Diketahui : s' = 32cm
f = 12cm
Ditanya : s...?
Jawab :
1/f = 1/s + 1/s'
1/12 = 1/s + 1/32
1/s = 1/12 - 1/32
1/s = 8/96 - 3/96
1/s = 5/96
s = 96/5
s = 19.2cm
Nyata
2.
Diketahui : d = 2.8cm
s = 25cm
f = -12cm
Ditanya : s'...?
d'/h'...?
Jawab :
1/f = 1/s + 1/s'
-1/12 = 1/25 + 1/s'
1/s' = -1/12 - 1/25
1/s' = -25/300 - 12/300
1/s' = -37/300
s' = -300/37
s' = -8.1
d=h
h'/h = s'/s
h'/2.8 = 8.1/25
h' = 8.1x2.8/25
h' = 0.9cm
Ismail Priyo Wicaksono(15) X-6
1. As we known :
s' = 32 cm (inverted image)
f = 12 cm (convex-convex (+))
The question :
s = ? is it real or virtual ?
Answer :
1/f=1/s + 1/s'
1/12=1/s + 1/32
1/s=8/96 - 3/96
1/s=5/96
s= 19,2 cm
because the image (+),so the image is real..
2. As we known :
Diameter of coin / h = 2,8 cm
s = 25 cm
f = -12 cm cause double concave lens
The question :
s' = ?
h' = ?
Answer :
1/f=1/s + 1/s'
1/-12=1/25 + 1/s'
1/s'=-12/300 - 25/300
1/s'=-37/300
s'=-8,1 cm (inverted)
|h'/h| = |-s'/s|
|h'/2,8| = |-(-8,1)/25|
|h'/2,8| = |8,1/25|
h'=2,8 x 8,1 : 25
h'=0,91 cm
Rido (21) X-4
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